Kubernetes POD delete with Pattern Match or Wildcard
When I am using below it deletes the running POD after matching the pattern from the command line:
kubectl get pods -n bi-dev --no-headers=true | awk '/group-react/{print $1}' | xargs kubectl delete -n bi-dev pod
However when I am using this command as an alias in .bash_profile it doesn't execute. This is how I defined it:
alias kdpgroup="kubectl get pods -n bi-dev --no-headers=true | awk '/group-react/{print $1}'| kubectl delete -n bi-dev pod"
When execute this as below I get an error in the command line:
~ $ kdpgroup error: resource(s) were provided, but no name, label selector, or --all flag specified
When I define this in .bash_profile I get this:
~ $ . ./.bash_profile -bash: alias: }| xargs kubectl delete -n bi-dev pod: not found ~ $
Am I missing something to delete POD using Pattern Match or with Wilcard?
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5 Answers
Am I missing something to delete POD using Pattern Match or with Wilcard?
When using Kubernetes it is more common to use labels and selectors. E.g. if you deployed an application, you usually set a label on the pods e.g.
app=my-appkubectl get pods -l app=my-appUsing this aproach, it is easier to delete the pods you are interested in, with e.g.
kubectl delete pods -l app=my-app
or with namespaces
kubectl delete pods -l app=my-app -n default
See more on Kubernetes Labels and Selectors
Set-based selector
I have some pod's running in the name of "superset-react" and "superset-graphql" and I want to search my wildcard superset and delete both of them in one command
I suggest that those pods has labels
app=something-reactapp=something-graphqlapp-type=reactapp-type=graphqlThen you can delete pods for both app types with this command:
kubectl delete pods -l 'app-type in (react, graphql)'
As the question asks, this is about using a wild card. Let me give examples on using wild cards to delete pods.
Delete Pods which contain the word "application"
Replace
<namespace>kubectl get pods -n <namespace> --no-headers=true | awk '/application/{print $1}'| xargs kubectl delete -n <namespace> pod
This will give a response like the following. It will print out the deleted pods.
pod "sre-application-7fb4f5bff9-8crgx" deleted pod "sre-application-7fb4f5bff9-ftzfd" deleted pod "sre-application-7fb4f5bff9-rrkt2" deleted
Delete Pods which contain "application" or "service"
Replace
<namespace>kubectl get pods -n <namespace> --no-headers=true | awk '/application|service/{print $1}'| xargs kubectl delete -n <namespace> pod
This will give a response like the following. It will print out the deleted pods.
pod "sre-application-7fb4f5bff9-8crgx" deleted pod "sre-application-7fb4f5bff9-ftzfd" deleted pod "sre-service-7fb4f5bff9-rrkt2" deleted
You just need to escape the '$1' variable in the awk command:
alias kdpgroup="kubectl get pods -n bi-dev --no-headers=true | awk '/group-react/{print \$1}'| xargs kubectl delete -n bi-dev pod"
I know that escape is boring, and if you want to avoid it you can use as a function in you .bash_profile:
kdpgroup() {
kubectl get pods -n default --no-headers=true | awk '{print $1}' | xargs kubectl delete pod -n default
}
using grep you can filter the keyword like this and delete matching pod name like this
kubectl get pods --no-headers=true | awk '{print $1}' | grep keyword | xargs kubectl delete pod
Mermoid diagram representation of the above command :
A robust way with variables, based on @keetSugathadasa answer:
ns="optional-namespace"
regex="pattern"
kubectl get pods ${ns:+ -n $ns} --no-headers | awk /${regex}/'{print $1}' \
| xargs kubectl delete ${ns:+ -n $ns} pod